A set mapping with no infinite free subsets

Journal of Symbolic Logic 56 (4):1400 - 1402 (1991)
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Abstract

It is consistent that there exists a set mapping $F: \lbrack\omega_2\rbrack^2 \rightarrow \lbrack\omega_2\rbrack^{<\omega}$ such that $F(\alpha, \beta) \subseteq \alpha$ for $\alpha < \beta < \omega_2$ and there is no infinite free subset for F. This solves a problem of A. Hajnal and A. Mate

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10.2307/2275484

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Remarks on superatomic boolean algebras.James E. Baumgartner & Saharon Shelah - 1987 - Annals of Pure and Applied Logic 33 (C):109-129.
Remarks on superatomic Boolean algebras.J. E. Baumgartner - 1987 - Annals of Pure and Applied Logic 33 (2):109.

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